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orAClE 递归

oracle递归查询 Oracle中start by prior子句用法 connect by 是结构化查询中用到的,其基本语法是: select ... from tablename start with 条件1 connect by 条件2 where 条件3; 例: select * from table start with org_id = 'HBHqfWGWPy' co...

关键字:START WITH ... CONNECT BY PRIOR select t.*,level from table_test t start with p_id = '3' connect by p_id = prior s_id; --查询p_id为3的所有子孙id select t.*,level from table_test t start with p_id = '3' connect by prior ...

select SYS_CONNECT_BY_PATH(列名,'>') from 表名 start wITh 列名='0000000001' connect by prior 列名(孩子列所有的列名)=列名(父列所有的列名) 这个查出来的样式如下: 000000000001>00000000>0000 不知道是不是你想要的。

楼主您好 可以试试connect by prior替换成connect by nocycle priororacle 中怎样递归查询出子节点的最上层父节点,并

select ename,mgr from employee start with mgr is null connect by ename =previous mgr;

楼主您好 可以试试connect by prior替换成connect by nocycle prior

相信你知道level在递归查询中的意思,除了level之外,还有一个伪列:CONNECT_BY_ISLEAF。你可以在输出的列中间加上CONNECT_BY_ISLEAF这个列,将会发现CONNECT_BY_ISLEAF为1的全是叶子节点,也就是你说的最底层。

这个链接中说oracle10g中用with as 了 http://www.itpub.net/forum.php?mod=viewthread&tid=1234453&page=1#pid14560709

可以的 --层次查询,自底到顶 select t.employee_id,t.last_name,t.job_id,t.manager_id,level from employees t start with t.employee_id=101 connect by prior t.manager_id=t.employee_id; select t.empno,t.ename,t.job,t.mgr,level from e...

查询父类ID为6的所有子类信息 select * from classinfo a start with classid=6 connet prior by classid=parentid

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