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group By hAving mAx

直接select max(num) 再group by 就行 不用后面的having

select id,姓名,开始日期,结束日期 from (select * from table order by 开始日期 desc) group by name

MIN(), MAX()是聚合函数. group by 后面是要跟着的 select 中所有不是聚合函数的字段。 ex1: select count(*) from emp; //只是查询总总数 emp这张表里一共有多少条记录 所以不用group by ex2: select count(*) , deptno from emp group by dept...

select cno from score group by cno having degree

为啥不想要你写的sql? 要找出分组计数最多的哪些组,必然要先算出最大的分组计数,只不过写法可以变通一下,但思路不变 with t as (select nodecol, count(1) cnt from tmp3 group by nodecol) select * from t where cnt=(select max(cnt) fro...

1、聚合函数可以嵌套2次,所以max(avg(sal))没有问题。 2、提示ORA-00937: not a single-group group function,是因为这已经是两层关系了。进行拆分就是: select max(a.str_avg),a.deptno from (select avg(sal) as str_avg,deptno from emp g...

UPDATE W SET W.A = ( SELECT W.A - S.A from S where W.G = S.G and S.N in(SELECT max(N) FROM S group by G ) ) where exists (select 1 from S where W.G = S.G and S.N in(SELECT max(N) FROM S group by G ) ) exists 语句很重要,否则如...

(1)一般而言在group by语句中,的结果显示只能是分组字段,如果有其他字段那么必须是带有聚合函数的,比如count,sum,max,min等,但是这里直接放个*就可以执行了? (2)如果是在group by之前筛选,那么怎么count,是选择oid=5的进行count么?...

select id,sfz,name,zp,time from t where (sfz,time) in (select sfz,max(time) from t group by sfz having time = max(time)) 这样做应该能行,但是还是感觉这个表本身没有设计好,时间最新的一条记录应该是客户当前状态,应该单表存放,不应...

譬如如下数据 id value 1 2 1 3 2 3 3 5 3 6 可以写个语句统计value的分组 select id,sum(value) from table group by id having sum(value)>=5 这样的结果就是 1 5 3 11 其实这句的意思就是 select id,sum(value) from table where sum(value)>...

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